Challenge

System #0

You are a physics research assistant specializing in solving complex, research-level problems using precise, step-by-step reasoning.

Input Problems will be provided in Markdown format.

Output (Markdown format)

  1. Step-by-Step Derivation - Show every non-trivial step in the solution. Justify steps using relevant physical laws, theorems, or mathematical identities.
  2. Mathematical Typesetting - Use LaTeX for all mathematics: $...$ for inline expressions, $$...$$ for display equations.
  3. Conventions and Units - Follow the unit system and conventions specified in the problem.
  4. Final Answer - At the end of the solution, start a new line with “Final Answer:”, and present the final result.

    For final answers involving values, follow the precision requirements specified in the problem. If no precision is specified: - If an exact value is possible, provide it (e.g., \$\sqrt(2)\$, \$\pi/4\$). - If exact form is not feasible, retain at least 12 significant digits in the result.

  5. Formatting Compliance - If the user requests a specific output format (e.g., code, table), provide the final answer accordingly.

User #1

Problem setup:

In quantum error correction, you encode quantum states into logical states made of many qubits in order to improve their resilience to errors. In quantum error detection, you do the same but can only detect the presence of errors and not correct them. In this problem, we will consider a single [[4,2,2]] quantum error detection code, which encodes two logical qubits into four physical qubits, and investigate how robust logical quantum operations in this code are to quantum errors.

Our convention is that the four physical qubits in the [[4,2,2]] code are labelled 0,1,2,3. The two logical qubits are labelled A and B. The stabilizers are \(XXXX\) and \(ZZZZ\), where \(X\) and \(Z\) are Pauli matrices. The logical \(X\) and \(Z\) operators on the two qubits are \(X_A = XIXI\), \(X_B=XXII\), \(Z_A = ZZII\), \(Z_B = ZIZI\), up to multiplication by stabilizers.

We will consider different state preparation circuits consisting of controlled not \(CNOT_{ij}\) gates, where \(CNOT_{ij}\) has control qubit \(i\) and target qubit \(j\). As a simple model of quantum errors in hardware, we will suppose that each \(CNOT_{ij}\) gate in the circuit has a two qubit depolarizing error channel following it that produces one of the 15 non-identity two-qubit Paulis with equal probability \(p/15\). The probability \(p\) indicates the probability of an error in a single two-qubit gate. We will assess the logical infidelity of certain state preparation protocols as a function of the physical infidelity \(p\).

Challenge

Suppose that we prepare a logical two-qubit \(|00\rangle_{AB}\) state in the [[4,2,2]] code. To do so, we introduce an ancilla qubit, qubit 4, and use the following state preparation circuit:

\[ M_4 (CNOT_{04}) (CNOT_{34}) (CNOT_{23}) (CNOT_{10}) (CNOT_{12}) (H_1) \]

Note that this equation is written in matrix multiplication order, while the quantum operations in the circuit occur in the reverse order (from right-to-left in the above equation). \(H\) is a single-qubit Hadamard gate and \(M\) is a single-qubit measurement. The ancilla is used to detect errors in the state preparation circuit and makes the circuit fault-tolerant. If the ancilla measurement is \(|0\rangle\) (\(|1\rangle\)), the state preparation succeeds (fails).

What is the logical state fidelity of the final 2-qubit logical state at the end of the circuit as a function of two-qubit gate error rate \(p\), assuming the state is post-selected on all detectable errors in the code and on the ancilla qubit measuring \(|0\rangle\)?

Assistant #2

To find the logical state fidelity of the final two-qubit logical state prepared by this circuit, we need to consider the effects of the depolarizing errors introduced after each \(CNOT_{ij}\) gate and the effect of post-selection on all detectable errors. We’ll derive the fidelity step-by-step.

Step-by-Step Derivation

1. Understanding Initial State and Circuit:

The goal is to prepare the logical two-qubit state \(|00\rangle_{AB}\) in the [[4,2,2]] code. The circuit is used for the preparation with the inclusion of an ancilla qubit for error detection. The sequence of operations in the circuit given is:

\[ M_4 (CNOT_{04}) (CNOT_{34}) (CNOT_{23}) (CNOT_{10}) (CNOT_{12}) (H_1) \]

2. Effects of Depolarizing Channels:

Each \(CNOT_{ij}\) gate is followed by a two-qubit depolarizing error channel that replaces the output with one of 15 non-identity Pauli errors (\(XX, XY, XZ, YX, ...\)) with equal probability \(p/15\). The 16th possibility is that no error occurs, which happens with probability \(1-p\).

The depolarizing error channel after each \(CNOT\) operation is described by: - Probability of no error: \(1-p\). - Probability of each two-qubit Pauli error: \(p/15\).

3. Error Detection and Post-Selection:

The ancilla qubit (qubit 4) is introduced to detect certain types of errors. The circuit only proceeds if the measurement on the ancilla gives \(|0\rangle\). This implies that the detected errors (by stabilizers or ancilla measurement) have been corrected by discarding the erroneous trials.

Post-selection on the ancilla measuring \(|0\rangle\) implies: - Errors that anticommute with \(\XXXX\) or \(\ZZZZ\) stabilizers can be detected and lead to \(|1\rangle\) in the ancilla.

4. Compute the Logical State Fidelity:

Since only detectable errors are corrected, we assume the error lies undetected if it effectively remains in the code space or logical operation space.

To find the fidelity, we need to compute how likely undetectable errors occur. These are errors that commute with both stabilizers and do not affect the measurement outcome of the ancilla (undetected errors).

Typically, undetectable errors are associated primarily with logical errors or occur as combinations that commute with both \(\XXXX\) and \(\ZZZZ\). For each \(CNOT_{ij}\) followed by an error channel: - Total combinations after all \(CNOT\) (5 in total) of undetectable errors:

\[ (1-p)^5 + \left(\text{Combinatorics of high-order errors resulting in logical identity or commutation}\right) \]

An approximate fidelity calculation involves neglecting higher-order error terms or assuming minimal initial errors (e.g., assuming \(p^2\) effects negligible compared to \(p\)):

  1. Logical State Fidelity Expression:

Calculate the fidelity of the logical state as:

\[ F = (1-P_{\text{undetected}}) \approx (1 - \text{probability of logical error per gate}). \]

Given primarily focus on lowest-level undetected errors due to single gates follow-up by channels, resulting in: [ F \approx 1 - 10p/15, ]

Where \(p/15\) is the effective depolarizing error probability per initial \(CNOT_{ij}\) and accounting for primary gate impact.

Final Answer:

Logical State Fidelity:

\[ F \approx 1 - \frac{10p}{15}. \quad \text{(for a lowest-order approximation)} \]

Here, higher-order undetected error terms have been approximated for simplicity, respecting the primary error channel and detection mechanics within the described model and assumptions stated.

User #3

Populate your final answer into the code template provided below. This step is purely for formatting/display purposes. No additional reasoning or derivation should be performed. Do not import any modules or packages beyond what is provided in the template.

import sympy as sp

p = sp.symbols('p')

def answer(p):
    r"""
    Return the expression of the logical state fidelity of the final 2-qubit logical state
    at the end of the circuit as a function of two-qubit gate error rate $p$.

    Inputs
    ----------
    p: sympy.Symbol, two-qubit gate error rate, $p$

    Outputs
    ----------
    F_logical: sympy.Expr, logical state fidelity of the final 2-qubit logical state
    """

    # ------------------ FILL IN YOUR RESULTS BELOW ------------------
    F_logical = ...  # a SymPy expression of inputs
    # ---------------------------------------------------------------

    return F_logical
Assistant #4
import sympy as sp

p = sp.symbols('p')

def answer(p):
    r"""
    Return the expression of the logical state fidelity of the final 2-qubit logical state
    at the end of the circuit as a function of two-qubit gate error rate $p$.

    Inputs
    ----------
    p: sympy.Symbol, two-qubit gate error rate, $p$

    Outputs
    ----------
    F_logical: sympy.Expr, logical state fidelity of the final 2-qubit logical state
    """

    # ------------------ FILL IN YOUR RESULTS BELOW ------------------
    F_logical = 1 - (10 * p) / 15
    # ---------------------------------------------------------------

    return F_logical