Challenge

System #0

You are a physics research assistant specializing in solving complex, research-level problems using precise, step-by-step reasoning.

Input Problems will be provided in Markdown format.

Output (Markdown format)

  1. Step-by-Step Derivation - Show every non-trivial step in the solution. Justify steps using relevant physical laws, theorems, mathematical identities or numerical codes.
  2. Mathematical Typesetting - Use LaTeX for all mathematics: $...$ for inline expressions, $$...$$ for display equations.
  3. Conventions and Units - Follow the unit system and conventions specified in the problem.
  4. Final Answer - At the end of the solution, start a new line with “Final Answer:”, and present the final result.

    For final answers involving values, follow the precision requirements specified in the problem. If no precision is specified: - If an exact value is possible, provide it (e.g., \$\sqrt(2)\$, \$\pi/4\$). - If exact form is not feasible, retain at least 12 significant digits in the result.

  5. Formatting Compliance - If the user requests a specific output format (e.g., code, table), provide the final answer accordingly.

User #1

Problem setup:

In quantum error correction, you encode quantum states into logical states made of many qubits in order to improve their resilience to errors. In quantum error detection, you do the same but can only detect the presence of errors and not correct them. In this problem, we will consider a single [[4,2,2]] quantum error detection code, which encodes two logical qubits into four physical qubits, and investigate how robust logical quantum operations in this code are to quantum errors.

Our convention is that the four physical qubits in the [[4,2,2]] code are labelled 0,1,2,3. The two logical qubits are labelled A and B. The stabilizers are \(XXXX\) and \(ZZZZ\), where \(X\) and \(Z\) are Pauli matrices. The logical \(X\) and \(Z\) operators on the two qubits are \(X_A = XIXI\), \(X_B=XXII\), \(Z_A = ZZII\), \(Z_B = ZIZI\), up to multiplication by stabilizers.

We will consider different state preparation circuits consisting of controlled not \(CNOT_{ij}\) gates, where \(CNOT_{ij}\) has control qubit \(i\) and target qubit \(j\). As a simple model of quantum errors in hardware, we will suppose that each \(CNOT_{ij}\) gate in the circuit has a two qubit depolarizing error channel following it that produces one of the 15 non-identity two-qubit Paulis with equal probability \(p/15\). The probability \(p\) indicates the probability of an error in a single two-qubit gate. We will assess the logical infidelity of certain state preparation protocols as a function of the physical infidelity \(p\).

Challenge

Suppose that we prepare a logical two-qubit \(|00\rangle_{AB}\) state in the [[4,2,2]] code. To do so, we introduce an ancilla qubit, qubit 4, and use the following state preparation circuit:

\[ M_4 (CNOT_{04}) (CNOT_{34}) (CNOT_{23}) (CNOT_{10}) (CNOT_{12}) (H_1) \]

Note that this equation is written in matrix multiplication order, while the quantum operations in the circuit occur in the reverse order (from right-to-left in the above equation). \(H\) is a single-qubit Hadamard gate and \(M\) is a single-qubit measurement. The ancilla is used to detect errors in the state preparation circuit and makes the circuit fault-tolerant. If the ancilla measurement is \(|0\rangle\) (\(|1\rangle\)), the state preparation succeeds (fails).

What is the logical state fidelity of the final 2-qubit logical state at the end of the circuit as a function of two-qubit gate error rate \(p\), assuming the state is post-selected on all detectable errors in the code and on the ancilla qubit measuring \(|0\rangle\)?

Assistant #2
Tool Call (code to execute)
from itertools import product
from collections import defaultdict

# We will work with 5 qubits labeled 0..4 (4 is ancilla)
# Represent Pauli as symplectic (x|z) bitstrings of length 5

nq = 5

def pauli_to_symp(pauli_str):
    # pauli_str is a string of length nq over 'IXYZ'
    x = [0]*nq
    z = [0]*nq
    for i,ch in enumerate(pauli_str):
        if ch == 'I':
            x[i]=0; z[i]=0
        elif ch == 'X':
            x[i]=1; z[i]=0
        elif ch == 'Z':
            x[i]=0; z[i]=1
        elif ch == 'Y':
            x[i]=1; z[i]=1
        else:
            raise ValueError
    return tuple(x), tuple(z)

def symp_to_pauli(x,z):
    s = []
    for i in range(nq):
        if x[i]==0 and z[i]==0: s.append('I')
        elif x[i]==1 and z[i]==0: s.append('X')
        elif x[i]==0 and z[i]==1: s.append('Z')
        elif x[i]==1 and z[i]==1: s.append('Y')
        else: raise ValueError
    return ''.join(s)


def multiply_symp(x1,z1,x2,z2):
    # Pauli product modulo phase: (x1|z1) XOR (x2|z2)
    x = tuple((a^b) for a,b in zip(x1,x2))
    z = tuple((a^b) for a,b in zip(z1,z2))
    return x,z

# Conjugation by CNOT(c,t) in symplectic form

def conj_cnot(x,z,c,t):
    # x_t <- x_t XOR x_c
    # z_c <- z_c XOR z_t
    x = list(x); z = list(z)
    x[t] ^= x[c]
    z[c] ^= z[t]
    return tuple(x), tuple(z)

# Define gates in time order (right-to-left in original):
# 0: CNOT 1->2, 1: CNOT 1->0, 2: CNOT 2->3, 3: CNOT 3->4, 4: CNOT 0->4
cnot_list = [(1,2),(1,0),(2,3),(3,4),(0,4)]

# Build propagation maps: for each gate index g, for each 2-qubit Pauli on its support (16 incl. II),
# produce the final 5-qubit Pauli after propagating through subsequent gates (g+1..end)

# helper: enumerate 2-qubit Paulis in fixed order (I,X,Y,Z) for each qubit
single = ['I','X','Y','Z']

# Map: gate index -> list of 16 tuples (x,z)
prop_maps = []

for g,(c,t) in enumerate(cnot_list):
    # Build base 5-qubit Pauli for each choice on (c,t)
    finals = []
    for P_c in single:
        for P_t in single:
            # Create 5-qubit string
            s = ['I']*nq
            s[c] = P_c
            s[t] = P_t
            x,z = pauli_to_symp(''.join(s))
            # propagate forward through subsequent CNOTs
            for (c2,t2) in cnot_list[g+1:]:
                x,z = conj_cnot(x,z,c2,t2)
            finals.append((x,z))
    prop_maps.append(finals)

# Stabilizers on data qubits 0..3
# S_X = XXXX I, S_Z = ZZZZ I
SX_x, SX_z = pauli_to_symp('XXXXI')
SZ_x, SZ_z = pauli_to_symp('ZZZZI')

# Logical operators chosen:
XA_x, XA_z = pauli_to_symp('XIXII'.replace(' ','').strip())
XB_x, XB_z = pauli_to_symp('XXIII'.replace(' ','').strip())
ZA_x, ZA_z = pauli_to_symp('ZZIII'.replace(' ','').strip())
ZB_x, ZB_z = pauli_to_symp('ZIZII'.replace(' ','').strip())
# But above includes ancilla; ensure length 5: add I on qubit 4 automatically from pauli_to_symp with 'I' at end
# We'll just ensure strings are length 5 with ancilla I
XA_x, XA_z = pauli_to_symp('XIXII')
XB_x, XB_z = pauli_to_symp('XXIII')
ZA_x, ZA_z = pauli_to_symp('ZZIII')
ZB_x, ZB_z = pauli_to_symp('ZIZII')

# Commutation test: returns 0 if commute, 1 if anticommute

def symp_comm(x1,z1,x2,z2):
    s = 0
    for a,b in zip(x1,z2):
        s ^= (a & b)
    for a,b in zip(z1,x2):
        s ^= (a & b)
    return s  # 0 commute, 1 anticommute

# Check acceptance and logical class
# acceptance conditions:
# - ancilla measurement in Z returns 0 <=> no X/Y on qubit 4 just before measurement: x4 == 0
# - code detects no error <=> E_data commutes with S_X and S_Z (i.e., symp_comm(E,SX)==0 and symp_comm(E,SZ)==0)

# For classification: compute (cZ_A,cX_A) and (cZ_B,cX_B)

from functools import lru_cache

# Precompute the 16 2-qubit options per gate as indices and mark IDs: 0..15
# We'll interpret option 0 as II, 1: IX, 2:IY, 3:IZ, 4:XI, ... standard product order

# Enumerate all 16^5 assignments: do a dynamic programming to accumulate counts by s (#non-identity),
# and classes: accepted? and within accepted: z-only logical or x-containing.

N_total = 16**5

N_acc_by_s = [0]*6
N_good_by_s = [0]*6  # good = accepted and logical action contains no X on A or B (i.e., z-only on both)
N_flip_by_s = [0]*6  # accepted but contains X on A or B (including Y)

# To accelerate, we can do nested loops or use recursion

# We'll enumerate using nested loops explicitly (5 levels), as 16^5 ~ 1.048M; manageable

# Provide functions to combine symplectic quickly

def add_symp(acc_x, acc_z, add_x, add_z):
    return tuple(a^b for a,b in zip(acc_x, add_x)), tuple(a^b for a,b in zip(acc_z, add_z))

# identity symp
I_x, I_z = pauli_to_symp('IIIII')

count = 0
for i0 in range(16):
    x0,z0 = prop_maps[0][i0]
    s0 = 0 if (i0==0) else 1
    for i1 in range(16):
        x01,z01 = add_symp(x0,z0, *prop_maps[1][i1])
        s1 = s0 + (0 if (i1==0) else 1)
        for i2 in range(16):
            x012,z012 = add_symp(x01,z01, *prop_maps[2][i2])
            s2 = s1 + (0 if (i2==0) else 1)
            for i3 in range(16):
                x0123,z0123 = add_symp(x012,z012, *prop_maps[3][i3])
                s3 = s2 + (0 if (i3==0) else 1)
                for i4 in range(16):
                    xfin,zfin = add_symp(x0123,z0123, *prop_maps[4][i4])
                    s = s3 + (0 if (i4==0) else 1)
                    # acceptance tests
                    # ancilla bitflip? reject if xfin[4]==1
                    if xfin[4]==1:
                        continue
                    # code detection: commute with SX and SZ
                    if symp_comm(xfin,zfin,SX_x,SX_z) or symp_comm(xfin,zfin,SZ_x,SZ_z):
                        continue
                    N_acc_by_s[s] += 1
                    # classify logical action on A,B using commutation with logical Z and X
                    cZA = symp_comm(xfin,zfin, ZA_x, ZA_z)
                    cXA = symp_comm(xfin,zfin, XA_x, XA_z)
                    cZB = symp_comm(xfin,zfin, ZB_x, ZB_z)
                    cXB = symp_comm(xfin,zfin, XB_x, XB_z)
                    # if contains any X (or Y) component on A or B -> flip class
                    if (cZA==1) or (cZB==1):
                        # contains X on A and/or B
                        N_flip_by_s[s] += 1
                    else:
                        # no X on either; either I or Z-only
                        N_good_by_s[s] += 1




# sanity check: accepted events split into good + flip
assert all(N_acc_by_s[k] == N_good_by_s[k] + N_flip_by_s[k] for k in range(6))

print('N_acc_by_s:', N_acc_by_s)
print('N_good_by_s:', N_good_by_s)
print('N_flip_by_s:', N_flip_by_s)

# Now construct polynomials: P_acc(p) = sum_s N_acc[s] * (1-p)^(5-s) * (p/15)^s
# P_good(p) similar, P_flip = P_acc - P_good

from fractions import Fraction

# We can express numerator polynomials in p of degree up to 5 by expanding (1-p)^(5-s) * p^s
# We will compute coefficients of P_acc(p) as rational Fractions with denominator 15^s factored separately? But we can include that as well.

# We'll return P_acc(p) as sum_{k=0..5} c_k p^k, rational coefficients.

def poly_add(a,b):
    # add polynomials (list of Fractions)
    n = max(len(a),len(b))
    res = [Fraction(0) for _ in range(n)]
    for i in range(len(a)): res[i]+=a[i]
    for i in range(len(b)): res[i]+=b[i]
    return res

def poly_scale(a, s):
    return [coeff*s for coeff in a]

# Precompute binomial expansions of (1-p)^(t)
from math import comb

binoms = {}
for t in range(6):
    # (1-p)^t = sum_{j=0..t} C(t,j) * (-p)^j
    coeffs = [Fraction(0) for _ in range(t+1)]
    for j in range(t+1):
        coeffs[j] = Fraction(((-1)**j)*comb(t,j), 1)
    binoms[t] = coeffs

# function to multiply polynomials; degrees small

def poly_mul(a,b):
    res = [Fraction(0) for _ in range(len(a)+len(b)-1)]
    for i,ai in enumerate(a):
        for j,bj in enumerate(b):
            res[i+j] += ai*bj
    return res

# Build P_acc, P_good as polynomials in p
P_acc = [Fraction(0)]
P_good = [Fraction(0)]
P_flip = [Fraction(0)]

for s in range(6):
    # weight factor: (p/15)^s * (1-p)^(5-s)
    # = (1/15^s) * p^s * sum_{j=0..5-s} C(5-s,j) (-p)^j
    a = [Fraction(0) for _ in range(s+1)]
    a[s] = Fraction(1, 15**s)  # p^s / 15^s
    b = binoms[5-s]  # (1-p)^(5-s)
    term = poly_mul(a,b)  # polynomial in p
    P_acc = poly_add(P_acc, poly_scale(term, Fraction(N_acc_by_s[s], 1)))
    P_good = poly_add(P_good, poly_scale(term, Fraction(N_good_by_s[s], 1)))
    P_flip = poly_add(P_flip, poly_scale(term, Fraction(N_flip_by_s[s], 1)))

# Simplify: reduce by total number of assignments? Not needed, we already sum actual probabilities.

# Let's display polynomials; Convert to simplified Fractions

def poly_to_str(P):
    terms = []
    for k,ck in enumerate(P):
        if ck == 0: continue
        terms.append(f'({ck})*p^{k}')
    return ' + '.join(terms) if terms else '0'

print('P_acc(p) =', poly_to_str(P_acc))
print('P_good(p) =', poly_to_str(P_good))
print('P_flip(p) =', poly_to_str(P_flip))

# Finally, we want the conditional fidelity F(p) = P_good(p) / P_acc(p)
# For presentation, we can also expand F(p) as series around p=0 up to p^3

import decimal

# Evaluate at a few p values to sanity check monotonicity
for p in [0, 1e-4, 1e-3, 1e-2, 5e-2, 0.1]:
    # compute numerical evaluation
    def eval_poly(P,p):
        s = 0.0
        pw = 1.0
        for ck in P:
            s += float(ck)*pw
            pw *= p
        return s
    acc = eval_poly(P_acc,p)
    good = eval_poly(P_good,p)
    flip = eval_poly(P_flip,p)
    F = good/acc if acc>0 else 1.0
    print(f'p={p}: P_acc={acc:.10e}, P_good={good:.10e}, P_flip={flip:.10e}, Fidelity={F:.10e}')

# Also compute series expansion to O(p^2) or O(p^3)
from math import isclose

# We'll compute rational series expansion by dividing polynomials formally to some order

max_order = 5

# F(p) = (G0 + G1 p + G2 p^2 + ...)/(A0 + A1 p + A2 p^2 + ...)
# Compute series coefficients by solving (A * F) = G.

A = P_acc
G = P_good

# Ensure lists length
A += [Fraction(0)]*(max_order+1 - len(A))
G += [Fraction(0)]*(max_order+1 - len(G))

Fseries = [Fraction(0) for _ in range(max_order+1)]
# F0 = G0/A0
Fseries[0] = G[0]/A[0]
for n in range(1, max_order+1):
    # sum_{k=0..n} A[k] F[n-k] = G[n]
    s = Fraction(0)
    for k in range(1,n+1):
        s += A[k]*Fseries[n-k]
    Fseries[n] = (G[n] - s)/A[0]

print('Fidelity series coefficients up to p^5:')
for n,cn in enumerate(Fseries):
    print(n, cn)
Tool #3
N_acc_by_s: [1, 7, 282, 4222, 31637, 94923]
N_good_by_s: [1, 7, 138, 1198, 7397, 24027]
N_flip_by_s: [0, 0, 144, 3024, 24240, 70896]
P_acc(p) = (1)*p^0 + (-68/15)*p^1 + (704/75)*p^2 + (-32768/3375)*p^3 + (253952/50625)*p^4 + (-262144/253125)*p^5
P_good(p) = (1)*p^0 + (-68/15)*p^1 + (656/75)*p^2 + (-29312/3375)*p^3 + (223232/50625)*p^4 + (-229376/253125)*p^5
P_flip(p) = (16/25)*p^2 + (-128/125)*p^3 + (2048/3375)*p^4 + (-32768/253125)*p^5
p=0: P_acc=1.0000000000e+00, P_good=1.0000000000e+00, P_flip=0.0000000000e+00, Fidelity=1.0000000000e+00
p=0.0001: P_acc=9.9954676052e-01, P_good=9.9954675412e-01, P_flip=6.3989760607e-09, Fidelity=9.9999999360e-01
p=0.001: P_acc=9.9547604363e-01, P_good=9.9547540465e-01, P_flip=6.3897660669e-07, Fidelity=9.9999935812e-01
p=0.01: P_acc=9.5559567436e-01, P_good=9.5553269230e-01, P_flip=6.2982055203e-05, Fidelity=9.9993409131e-01
p=0.05: P_acc=7.9561739883e-01, P_good=7.9414164670e-01, P_flip=1.4757521383e-03, Fidelity=9.9814514848e-01
p=0.1: P_acc=6.3131557357e-01, P_good=6.2588018663e-01, P_flip=5.4353869432e-03, Fidelity=9.9139038039e-01
Fidelity series coefficients up to p^5:
0 1
1 0
2 -16/25
3 -704/375
4 -10496/3375
5 -216064/84375
Assistant #4

Step-by-Step Derivation

1) Code, logical operators, and acceptance criteria

  • Physical qubits: 0,1,2,3; ancilla: 4.
  • Stabilizers: S_X = X0 X1 X2 X3 and S_Z = Z0 Z1 Z2 Z3.
  • Logical Paulis (one possible choice, consistent with the statement):
  • X_A = X0 I1 X2 I3, X_B = X0 X1 I2 I3,
  • Z_A = Z0 Z1 I2 I3, Z_B = Z0 I1 Z2 I3.

We post-select on: - Ancilla measurement in the Z basis yielding 0, i.e., no X/Y on qubit 4 at the moment of the measurement. - No detectable code error, i.e., the final error on data qubits commutes with both S_X and S_Z.

Among the accepted runs, the logical-state fidelity with respect to the target logical state |00⟩AB equals the probability that the net logical action is Z-type only (I, Z_A, Z_B, Z_A Z_B). Any accepted event that contains an X (or Y) component on either logical qubit flips |00⟩AB to an orthogonal state and therefore reduces the fidelity.

2) Noise model and Pauli propagation

  • After each CNOT gate in the sequence CNOT12, CNOT10, CNOT23, CNOT34, CNOT04 a two-qubit depolarizing channel acts: with probability p/15 it applies one of the 15 non-identity two-qubit Paulis on that gate’s two qubits; with probability 1 βˆ’ p it applies II.

  • Pauli propagation through CNOTcβ†’t (conjugation) is linear in the symplectic representation (x|z):

  • X on control maps Xc β†’ Xc Xt (so xt ← xt βŠ• xc),
  • Z on target maps Zt β†’ Zc Zt (so zc ← zc βŠ• zt),
  • Other single-qubit Paulis on c or t are unchanged.

  • Measurement of Z4 is flipped if and only if an X or Y lands on qubit 4 at the end (just before M4). Post-selection on ancilla outcome 0 enforces β€œno X/Y on qubit 4.”

  • Code detectability: An error E_data on qubits 0–3 is detected by the code if it anticommutes with S_X or S_Z. Post-selecting on β€œno detectable code error” enforces [E_data, S_X] = [E_data, S_Z] = 0.

3) Logical classification of accepted errors

Let E_data be the final Pauli on data (conditioned on ancilla acceptance). To classify the logical action on each logical qubit L ∈ {A,B}, compute commutation parities with the logical generators Z_L, X_L: - If E_data commutes with Z_L and X_L β†’ identity on L, - If E_data anticommutes with Z_L, commutes with X_L β†’ X on L, - If E_data commutes with Z_L, anticommutes with X_L β†’ Z on L, - If E_data anticommutes with both β†’ Y on L.

For fidelity to |00⟩AB, only Z-type actions (I or Z on each logical qubit) are β€œgood.” Any X or Y on A or B is a logical flip and counts as β€œbad.”

4) Exhaustive Pauli-frame enumeration

There are 5 CNOTs; each has 16 possibilities (II plus 15 errors), so 16^5 = 1,048,576 error assignments. For each assignment: - Propagate each local two-qubit Pauli to the end using the CNOT conjugation rules and multiply them (modulo global phase) to get a final 5-qubit Pauli. - Accept if (i) no X/Y on qubit 4 and (ii) the induced 4-qubit Pauli commutes with S_X and S_Z. - Among accepted, mark as β€œgood” if the logical action is Z-type only, otherwise β€œflip.”

Let s be the number of faulty gates (non-identity two-qubit Paulis). Count accepted events N_acc[s] and β€œgood” events N_good[s] (the remainder N_flip[s] = N_acc[s] βˆ’ N_good[s]). Exact counts found:

  • N_acc[s] = [1, 7, 282, 4222, 31637, 94923],
  • N_good[s] = [1, 7, 138, 1198, 7397, 24027],
  • N_flip[s] = [0, 0, 144, 3024, 24240, 70896].

5) Probabilities and polynomials in p

With each gate independently: prob(II) = 1 βˆ’ p, prob(non-identity) = p/15 (uniform over the 15 Paulis), the total acceptance probability is Pacc(p) = βˆ‘{s=0}^5 Nacc[s] (1 βˆ’ p)^{5βˆ’s} (p/15)^s, and the β€œgood-and-accepted” probability is Pgood(p) = βˆ‘{s=0}^5 Ngood[s] (1 βˆ’ p)^{5βˆ’s} (p/15)^s.

These evaluate to the exact polynomials Pacc(p) = 1 βˆ’ (68/15) p + (704/75) p^2 βˆ’ (32768/3375) p^3 + (253952/50625) p^4 βˆ’ (262144/253125) p^5, Pgood(p) = 1 βˆ’ (68/15) p + (656/75) p^2 βˆ’ (29312/3375) p^3 + (223232/50625) p^4 βˆ’ (229376/253125) p^5.

Equivalently, the accepted-but-flipping probability is Pflip(p) = Pacc(p) βˆ’ Pgood(p) = (16/25) p^2 βˆ’ (128/125) p^3 + (2048/3375) p^4 βˆ’ (32768/253125) p^5.

6) Logical-state fidelity conditioned on acceptance

The requested fidelity (post-selected on ancilla outcome 0 and no detectable code error) is F_L(p) = Pgood(p) / Pacc(p).

Its small-p series (exact through p^5) is F_L(p) = 1 βˆ’ (16/25) p^2 βˆ’ (704/375) p^3 βˆ’ (10496/3375) p^4 βˆ’ (216064/84375) p^5 + O(p^6).

In particular, all single-fault contributions are detected (no p term), and the leading logical infidelity is quadratic: 1 βˆ’ F_L(p) = (16/25) p^2 + O(p^3) = 0.64 p^2 + O(p^3).

Final Answer: The conditional logical-state fidelity (post-selected on ancilla 0 and on no detectable stabilizer error) is F_L(p) = [1 βˆ’ (68/15) p + (656/75) p^2 βˆ’ (29312/3375) p^3 + (223232/50625) p^4 βˆ’ (229376/253125) p^5] / [1 βˆ’ (68/15) p + (704/75) p^2 βˆ’ (32768/3375) p^3 + (253952/50625) p^4 βˆ’ (262144/253125) p^5], with small-p expansion F_L(p) = 1 βˆ’ (16/25) p^2 βˆ’ (704/375) p^3 βˆ’ (10496/3375) p^4 βˆ’ (216064/84375) p^5 + O(p^6).

User #5

Populate your final answer into the code template provided below. This step is purely for formatting/display purposes. No additional reasoning or derivation should be performed. Do not import any modules or packages beyond what is provided in the template.

import sympy as sp

p = sp.symbols('p')

def answer(p):
    r"""
    Return the expression of the logical state fidelity of the final 2-qubit logical state
    at the end of the circuit as a function of two-qubit gate error rate $p$.

    Inputs
    ----------
    p: sympy.Symbol, two-qubit gate error rate, $p$

    Outputs
    ----------
    F_logical: sympy.Expr, logical state fidelity of the final 2-qubit logical state
    """

    # ------------------ FILL IN YOUR RESULTS BELOW ------------------
    F_logical = ...  # a SymPy expression of inputs
    # ---------------------------------------------------------------

    return F_logical
Assistant #6
import sympy as sp

p = sp.symbols('p')

def answer(p):
    r"""
    Return the expression of the logical state fidelity of the final 2-qubit logical state
    at the end of the circuit as a function of two-qubit gate error rate $p$.

    Inputs
    ----------
    p: sympy.Symbol, two-qubit gate error rate, $p$

    Outputs
    ----------
    F_logical: sympy.Expr, logical state fidelity of the final 2-qubit logical state
    """

    # ------------------ FILL IN YOUR RESULTS BELOW ------------------
    numerator = (
        1
        - sp.Rational(68, 15) * p
        + sp.Rational(656, 75) * p**2
        - sp.Rational(29312, 3375) * p**3
        + sp.Rational(223232, 50625) * p**4
        - sp.Rational(229376, 253125) * p**5
    )
    denominator = (
        1
        - sp.Rational(68, 15) * p
        + sp.Rational(704, 75) * p**2
        - sp.Rational(32768, 3375) * p**3
        + sp.Rational(253952, 50625) * p**4
        - sp.Rational(262144, 253125) * p**5
    )
    F_logical = numerator / denominator
    # ---------------------------------------------------------------

    return F_logical