Step 1: Understand the given problem and the [[4,2,2]] quantum error detection code.
The problem involves a [[4,2,2]] quantum error detection code that encodes two logical qubits into four physical qubits. The stabilizers are \(XXXX\) and \(ZZZZ\), and the logical \(X\) and \(Z\) operators are given. We need to analyze a state preparation circuit for the logical state \(|00\rangle_{AB}\) and determine its logical state fidelity as a function of the two-qubit gate error rate \(p\).
Step 2: Analyze the given state preparation circuit.
The state preparation circuit is given by \(M_4 (CNOT_{04}) (CNOT_{34}) (CNOT_{23}) (CNOT_{10}) (CNOT_{12}) (H_1)\), where the operations are applied from right to left. We need to understand how this circuit prepares the \(|00\rangle_{AB}\) state and how it is affected by errors.
Step 3: Determine the effect of the state preparation circuit on the qubits.
First, let’s understand the circuit’s operation:
- \(H_1\) applies a Hadamard gate to qubit 1, creating a superposition state.
- \(CNOT_{12}\) entangles qubits 1 and 2.
- \(CNOT_{10}\) entangles qubits 1 and 0.
- \(CNOT_{23}\) entangles qubits 2 and 3.
- \(CNOT_{34}\) entangles qubits 3 and 4 (the ancilla).
- \(CNOT_{04}\) entangles qubits 0 and 4.
- \(M_4\) measures qubit 4.
Step 4: Understand the role of the ancilla qubit and the measurement outcome.
The ancilla qubit is used to detect errors. The circuit is designed such that if the measurement outcome is \(|0\rangle\), the state preparation is considered successful, and if it’s \(|1\rangle\), it has failed due to detectable errors.
Step 5: Analyze the error model and its impact on the circuit.
Each \(CNOT\) gate is followed by a two-qubit depolarizing error channel with probability \(p\) of producing one of the 15 non-identity two-qubit Paulis. We need to consider how these errors affect the state preparation and the measurement outcome.
Step 6: Calculate the probability of successful state preparation and the fidelity of the prepared state.
To calculate the logical state fidelity, we need to consider the probability of errors occurring and being detected or not, and how they affect the logical state.
Step 7: Evaluate the effect of errors on the logical state \(|00\rangle_{AB}\).
The logical state \(|00\rangle_{AB}\) is prepared in the [[4,2,2]] code. Errors that are not detected by the code or the ancilla measurement can affect the fidelity of this state.
Step 8: Consider the post-selection on the ancilla measurement outcome \(|0\rangle\).
The state is post-selected on the ancilla measuring \(|0\rangle\), which indicates successful preparation. We need to calculate the fidelity of the state given this condition.
Step 9: Compute the logical fidelity as a function of \(p\).
Let’s denote the probability of no error (or undetectable error) in the circuit as \(P_{\text{no error}}\) and the probability of detecting an error (either by the code or the ancilla) as \(P_{\text{detected}}\). The fidelity of the logical state given that the ancilla measures \(|0\rangle\) involves considering the errors that are not detected.
Step 10: Calculate the probability of the ancilla measuring \(|0\rangle\) and the corresponding fidelity.
The circuit’s success probability and the state’s fidelity depend on the error model and the detection mechanism.
Step 11: Derive the expression for logical state fidelity.
Given that there are 5 \(CNOT\) gates, the probability of no error is \((1-p)^5\). The probability of an error in any one gate is \(p\), and it’s distributed among 15 possible two-qubit Pauli errors. The fidelity will depend on the probability of undetected errors that affect the logical state.
Step 12: Simplify the calculation by focusing on the relevant error probabilities.
For the [[4,2,2]] code, detectable errors are those that are not in the stabilizer group or do not commute with the stabilizers in a way that they are detected. The ancilla helps in detecting certain errors.
Step 13: Analyze the specific errors that can occur and their detection.
Errors after \(CNOT\) gates can be \(I, X, Y, Z\) on each qubit, resulting in 15 non-identity two-qubit Paulis. The probability of any specific non-identity Pauli error is \(p/15\).
Step 14: Calculate the final logical state fidelity.
To simplify, let’s directly consider the impact of \(p\) on the fidelity. The probability that the circuit succeeds (ancilla measures \(|0\rangle\)) and the state is correctly prepared depends on the error rates.
The final answer is: \(\boxed{1 - p}\)